It would be very interesting to see tables of plans of stratagy on how to get to the magic million with the least number of games etc...
End of quote
I guess I can answer this one.
First a small reminder:
games are stocked in block:
block 0 : games aged from 0 to 30 days, no aging
block 1 : 31-60, 5% aging
block 2 : 61-90, 10% aging
block 3 : 91-120, 15% aging
block 4 : 121-150, 20% aging
block 5 : 151-220, 25% aging
block 6 : 221-290, 30% aging
block 7: 291 and more, 35% aging
The points in a block is: sum(raw total)* (1-aging)/squareroot(number of games) = average * squareroot(number of game) * (1-aging).
If N is the number of games submitted in 30 days.
To reach 1 Millions points with 60K games it needs:
- with only block 0: 1000K = 60K*sqrt(N)=> sqrt(N) = 50/3 = 16.667 => N = 278 (more than 9 games per day). total submitted games: 1*278 = 278
- with block 0 and 1: 1000K = 60K*sqrt(N)* (1 + 0.95)=> sqrt(N) = 50/(3*1.95) => N = 74 (more than 2 games per day). Total submitted games: 2*74 = 148
- up to block 2: 1000K = 60K*sqrt(N)*(1 + 0.95 + 0.9) => sqrt(N) = 50/(3*2.85) => N = 35 (a little more than 1 game per day). Total submitted games: 3*35 = 105
- up to block 3: 1000K = 60K*sqrt(N)*(1 + 0.95 + 0.9 + 0.85) => sqrt(N) = 50/(3*3.7) => N = 21 (2 games every 3 days). Total submitted games: 4*21 = 84
- up to block 4: 1000K = 60K*sqrt(N)*(1 + 0.95 + 0.9 + 0.85 + 0.8) => sqrt(N) = 50/(3*4.5) => N = 14 (1 game every 2 days). Total submitted games: 5*14 = 70
- up to 30 days in block 5: 1000K = 60K*sqrt(N)*(1 + 0.95 + 0.9 + 0.85 + 0.8 + 0.75) => sqrt(N) = 50/(3*5.25) => N = 11 (1 game every 3 days). Total submitted games: 6*11 = 66
- up to 70 days in block 5: 1000K = 60K*sqrt(N)*(1 + 0.95 + 0.9 + 0.85 + 0.8 + 0.75*70/30) => sqrt(N) = 50/(3*6.25) => N = 8 (between 1 game every 3 days and 1 every 4 days). Total submitted games: 8*5 + 8*7/3 = 58
- up to 30 days in block 6: 1000K = 60K*sqrt(N)*(1 + 0.95 + 0.9 + 0.85 + 0.8 + 0.75*70/30 + 0.7) => sqrt(N) = 50/(3*6.95) => N = 6 (between 1 game every 5 days). Total submitted games: 6*6 + 6*7/3 = 50
- up to 70 days in block 6: 1000K = 60K*sqrt(N)*(1 + 0.95 + 0.9 + 0.85 + 0.8 + 0.75*70/30 + 0.7*70/30) => sqrt(N) = 50/(3*7.88) => N = 5 (between 1 game every 6 days). Total submitted games: 5*5 + 2*5*7/3 = 48
- up to 30 days in block 7: 1000K = 60K*sqrt(N)*(1 + 0.95 + 0.9 + 0.85 + 0.8 + 0.75*70/30 + 0.7*70/30 + 0.65) => sqrt(N) = 50/(3*8.53) => N = 4 (1 game every week). Total submitted games: 4*6 + 2*4*7/3 = 42.
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